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The amount of gas that occupies 60.82 Lat 310 K and 367 mm Hg is mol. hint: use ideal gas law PV-nRT, and 1 atm - 760 mmHg, g
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Ideal gas law pV = nRT p= pressure V=Volume we know that n=mol R= constant 760 mmHg = 1 atm T= Tempareture 367 mmHg = 367 81. pv=nRT n= DV = 0.48 atm x 60.826 0.082 Latma ki moi x31.0k = 11.48 mol i. The amount of gas that occupies 60.822 at 31.ok

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