Question

In southern California, a growing number of individuals pursuing teaching credentials are choosing paid internships over traditional student teaching programs. A group of thirteen candidates for six local teaching positions consisted of seven who had enrolled in paid internships and six who enrolled in traditional student teaching programs. All thirteen candidates appear to be equally qualified, so six are randomly selected to fill the open positions. Let y be the number of internship trained candidates who are hired. (a) Does Y have a binomial or hypergeometric distribution? Why? A binomial distribution, as the probability of being chosen on a trial is dependent of the outcomes of previous trials. A hypergeometric distribution, as the probability of being chosen on a trial is independent of the outcomes of previous trials. O A binomial distribution, as the probability of being chosen on a trial is either a success or a failure. A hypergeometric distribution, as the probability of being chosen on a trial is dependent on the outcome of previous trials. (b) Find the probability that five or more internship trained candidates are hired. (Round your answer to four decimal places.) (c) What is the mean and standard deviation of Y? (Round your answers to four decimal places.) 0 = Need Help? Read It Talk to a Tutor

Answer 1

solutions:- (a) D A Hyber geometric distribution, trials are dependenct (b) Plast = P(x=5) + P 1x=6) +846A) = (?) 19) + (216) - 10.0475 C) e na 9x213.2308 A+B 7 + 6 6x7x6 (7+6) 2 13 13 - 6 -1 0.93 26