Question

) As part of the mechanism of a catapult, a 5.0 m-long aluminum wire with a diameter of 0.5 cm is stretched due to a force of 1000.0 N. Calculate the amount this cable has been stretched. b) A projectile is launched upwards and reaches a maximum height of 50.0 m. How long after reaching this height does it take the object to reach the ground? c) During another launch, the projectile broke into two pieces. Each has its own projectile motion and path. How can we still analyze the pieces as part of a system? Sketch a diagram indicating the initial and final momentum of this system. No calculations are necessary. d) Once the fragments land on the ground, a person picks up a 500.0 g piece, ties a long string around it and rotates it overhead at a rate of 3.0 rev/s. The distance from their hand to the fragment is 0.8 m. Calculate the force required for this fragment to rotate with constant velocity. e) Sketch the centripetal acceleration, the force from part d) and the tangential velocity acting on the fragment.Question 2 (20 points) a) As part of the mechanism of a catapult, a 5.0 m-long aluminum wire with a diameter of 0.5 cm is str

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Answer #1

so (2 a L = 5m De 0.5 cm = 5x1063m } Cuiven pata P 1000N SL = Apmount of Apmount of Cable stretched. As we knew formula is SLGiven Data Ha 50m put in @ 50 - y 2 S, 28 70 Vo sind = 1009 2 sin2o 21 (00Put (3) in 20 s Z V4.81 g Time of fligh & flight 2x10vg t=6.3865 Time taken after reaching maxim height take the object to re

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