how many oxygen atoms are in 2.40 g of quartz?

Question

Question

Answer 1

Answer #1

Quartz formula is SiO2

no of oxygen atoms = mass of substance*6.023*10²³ *atomicity/Gram molar mass

gram molar mass of SiO2 = 28+32 = 60g/mole

Atomicity of Oxygen in SiO2 = 2

no of oxygen atoms = mass of SiO2* 6.023*10²³ * atomicity of oxygen in SiO2/Gram molar mass of SiO2

= 2.4*6.023*10²³ *2/60 = 4.8*10²² oxygen atoms

Answer 2

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