BSA (ug/ul) Volume of solution used for loading on the gel Total amount of BSA loaded on the gel
1.6 15 ul 1.6 X 15= 24 ug
0.8 15 ul 0.8 X 15 = 12 ug
0.4 15 ul 0.4 X 15= 6 ug
0.2 15 ul 0.2 X 15= 3 ug
0.1 15 ul 0.1 X 15 = 1.5 ug
Calculate the final amount (ug) of BSA that used for standard curve. Show your calculations. the...
En (2 points) You isolated your mitochondrial DNA in Part I. In step 6, you discard the supernatant, but keep the pellet. In step 15, you discard the pellet, but keep the supernatant. Explain why the pattern is different between the two steps and the consequence of mixing up these two steps. Procedure Part 1: mt DNA Isolation from your cheek cells. Lysis solution is used to breakdown the cells in this step, you will isolate MEONA from cheek cells....