Answer is B If y(t) is the solution of the initial value problem then y(t) =?...
The solution of the initial value problem y" + 4y = g(t); y(0) = -1, y'(0) = 4 is ОВ. cos 2t y = į SÓ 9(T) sin 2(t – 7)dt + 2 sin 2t – cos 2t y = {G(s) sin 2t + 2 sin 2t y = So 9(7) sin 2(t – 7)dt + 2 sin 2t – į cos 2t y = £g(t) sin 2t + 2 sin 2t – } oc OD COS 2t OE y...
Find the solution of the initial value problem y" – 2y' + 5y = g(t), y(0) = 0, y'(0) = 0, where g(t) is a continuous, otherwise arbitrary, function. Oy(t) = g(t) 1 y(t) = (sets sin(2t))g(t) Oy(t) = (cos(2t)) * g(t) Oy(t) = (cos(2t))g(t) y(t) = (1 e*) + f(t) x(t) =() e sin(26)g(t) g(t) = ( e sin(2t) + (t) y(t) = Ce+ sin(2t)) *g(t) 1
6. Solve the initial value problem y" + y = 0, y(0)=0, y'0=1 (a) -COS X (b) -sin x (c) -sin x + cos x (d) -sin x COS X (e) COS X (f) sin x (g) sin x-COS X (h) sin x + cos x 7. Find a particular solution yn of the differential equation (using the method of undetermined coefficients): y + y =p2 (a) 2e (b) 3e (c) 4e: (d) 6e (e) 2/2 (f) e2/3 (g) e2/4...
1 point) Consider the initial value problem dy 29y--9e cos( dt dt2 dt Write down the Laplace transform of the left-hand side of the equation given the initial conditions Y(sA2-10s+29)+3s-24 Your answer should be a function of s and Y with Y denoting the Laplace transform of the solution y. Write down the Laplace transform of the right-hand side of the equation -9(s-5(S-5)A2+9) Your answer should be a function of s only. Next equate your last two answers and solve...
use the Laplace transform to solve the given initial value problem: Only problem 4,8 and 12 please 4. y" – 4y' + 4y = 0; y(0) = 1, y'(0) = 1 5. y" – 2y' + 4y = 0; y(0) = 2, y'(0) = 0 Σ Answer Solution = e 6. y" + 4y' + 297 - 2t sin 5t; y(0) = 5, 7. y" +12y = cos 2t, 22 # 4; y(0) = 1, : > Answer > Solution...
Chapter 3, Section 3.5, Question 15 Find the solution of the initial value problem y" + 2y' + 5У-16e-t cos (2t), y (0)-4, y, (0-0. Enclose arguments of functions in parentheses. For example, sin (2x) Equation Editor Ω Common Matrix 亩。 sin(a) ca) tanta) sec(a) ese(a cot(a sin (a) y (t) Click if you would like to Show Work for this question: Open Show Work Chapter 3, Section 3.5, Question 15 Find the solution of the initial value problem y"...
y(t) is INCORRECT but x(t) is CORRECT DIFFERENTIAL EQUATIONS / Linear Algebra Only people that are proficient in DIFFERENTIAL EQUATIONS should even attempt to solve. No beginners or amateurs allowed. Please write clearly and legibly. No sloppy Handwriting. I must be able to clearly and easily read your solution and answer. Circle final answer. BELOW is an example of what the answer should look very similar to. should be in the same form basically. example 7.10.4 Question Help Use the...
Solve for Y(s), the Laplace transform of the solution y(t) to the initial value problem below. y' + 5y = 5t? -9, y(0) = 0, y'(0) = -3 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. 169=122 3.sin (1960) - cos (15) -
Problem 3: Solve the initial value problem and write your solution as a piecewise func- tion: y () y(0) A,y(0) with cos(2t), cos (2t) +cos (2t - 12), t2 6 f(t)
QUESTION 3 After use Laplace Transform to transform the following initial value problem X" +x=e-t, x(0) = 1,x'(0) = 1, S-2 you should get X(s)= (write fraction as (S-2)/(5-4)(8+6) for -). Then, find (s-4)(8+6) x(t)= L-?{X(s)}= (write 5/6 by 5 -30 6' e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).