The solution of the initial value problem y" + 4y = g(t); y(0) = -1, y'(0)...
Find the solution of the initial value problem y" – 2y' + 5y = g(t), y(0) = 0, y'(0) = 0, where g(t) is a continuous, otherwise arbitrary, function. Oy(t) = g(t) 1 y(t) = (sets sin(2t))g(t) Oy(t) = (cos(2t)) * g(t) Oy(t) = (cos(2t))g(t) y(t) = (1 e*) + f(t) x(t) =() e sin(26)g(t) g(t) = ( e sin(2t) + (t) y(t) = Ce+ sin(2t)) *g(t) 1
Please help me with c. (1 point) Consider the initial value problem y" 4y g(t), y(0) 0, y(0) = 0, if 0<t4 where g(t) if 4too a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transfom of y(t) by Y (8). Do not move any terms from one side of the equation to the other (until you get to part (b) below). ... s 2Y(s)+4Y(s) (e(-4s)-s)(4+1/s)+1/ s^2...
Answer is B If y(t) is the solution of the initial value problem then y(t) =? A. u5(t)e2f sin t B. us(t)e2t+10 sin(t - 5) C. s(t2t-5 sin(2t - 10) 2 D. us(t)e2-5 sin(t - 5) E. ušt)e-2t+10 cos(t-5
Which of the following is the solution to the initial value problem - 4y = 0, y(0) = 2, y'(0) = 0? (A.) y = 2 cos(2x) (B.) y = 2 sin(2x) (C.) y = 2e20 (D.) yr e-2x + 20 (E.) y = 2e2x – 4.ce 2.
17. Use the Laplace transform to solve the initial value problem: y" + 4y' + 4y = 2e-, y(0) = 1, (O) = 3. 18. Use the Laplace transform to solve the initial value problem: 4y" – 4y + 5y = 4 sin(t) – 4 cos(1), y(0) = 0, y(0) = 11/17.
Find the solution of the initial value problem y′′+4y=t^2+6e^t, y(0)=0, y′(0)=5. Enter an exact answer. Enclose arguments of functions in parentheses. For example, sin(2x).
use the Laplace transform to solve the given initial value problem: Only problem 4,8 and 12 please 4. y" – 4y' + 4y = 0; y(0) = 1, y'(0) = 1 5. y" – 2y' + 4y = 0; y(0) = 2, y'(0) = 0 Σ Answer Solution = e 6. y" + 4y' + 297 - 2t sin 5t; y(0) = 5, 7. y" +12y = cos 2t, 22 # 4; y(0) = 1, : > Answer > Solution...
Use the Laplace transform to solve the initial value problem: y' + 4y = cos(2t), y(0) = 0, y'(0 = 1.
solve it with matlab 25.24 Given the initial conditions, y(0) = 1 and y'(0) = 1 and y'(0) = 0, solve the following initial-value problem from t = 0 to 4: dy + 4y = 0 dt² Obtain your solutions with (a) Euler's method and (b) the fourth- order RK method. In both cases, use a step size of 0.125. Plot both solutions on the same graph along with the exact solution y = cos 2t.
Question 7 < > Solve the initial-value problem using the Method of Undeterminded Coefficients: y' + 4y = 10 cos(2t) y(0) = 1 y'(0) = 1 g(t) = Submit Question