Which of the following is the solution to the initial value problem - 4y = 0,...
The solution of the initial value problem y" + 4y = g(t); y(0) = -1, y'(0) = 4 is ОВ. cos 2t y = į SÓ 9(T) sin 2(t – 7)dt + 2 sin 2t – cos 2t y = {G(s) sin 2t + 2 sin 2t y = So 9(7) sin 2(t – 7)dt + 2 sin 2t – į cos 2t y = £g(t) sin 2t + 2 sin 2t – } oc OD COS 2t OE y...
3) Solve the initial value problem. a) nie - 2x(y2 – 2y) = 0, with y(0) = 4 b) (-4y cos x + 4 sin I Cos I + sec? x)dx + (4y - 4 sin x)dy = 0, with y ) = 1
17. Use the Laplace transform to solve the initial value problem: y" + 4y' + 4y = 2e-, y(0) = 1, (O) = 3. 18. Use the Laplace transform to solve the initial value problem: 4y" – 4y + 5y = 4 sin(t) – 4 cos(1), y(0) = 0, y(0) = 11/17.
Find the solution of the initial value problem y′′+4y=t^2+6e^t, y(0)=0, y′(0)=5. Enter an exact answer. Enclose arguments of functions in parentheses. For example, sin(2x).
Find the general solution of y” + 4y' + 5y = 0. Select one: • a. y = {-2x (cos(x) + sin(x)) b. y = e-24 (A cos(x) + B sin(x)) c.y = Cje-2x (cos(x) + sin(x)) O d. y = e*(A cos(2x) + B sin(2x))
(10 point) Solve the following initial value problems. a) y"+ 4y' + 8y = 40cos(2x), y(0) = 8, y'(0) = 0 b) y" + 6y' + 13y = 12e-3xsin(2x), y(0) = 0, y'(0) = 0 (10 point) Find a general solution of each of the following nonhomogeneous equations. a) y" + 4y = 12x−8cos(2x) b) y(4)− 4y" = 16+32sin(2x)
6. Solve the initial value problem y" + y = 0, y(0)=0, y'0=1 (a) -COS X (b) -sin x (c) -sin x + cos x (d) -sin x COS X (e) COS X (f) sin x (g) sin x-COS X (h) sin x + cos x 7. Find a particular solution yn of the differential equation (using the method of undetermined coefficients): y + y =p2 (a) 2e (b) 3e (c) 4e: (d) 6e (e) 2/2 (f) e2/3 (g) e2/4...
Find the solution of the initial value problem y" – 2y' + 5y = g(t), y(0) = 0, y'(0) = 0, where g(t) is a continuous, otherwise arbitrary, function. Oy(t) = g(t) 1 y(t) = (sets sin(2t))g(t) Oy(t) = (cos(2t)) * g(t) Oy(t) = (cos(2t))g(t) y(t) = (1 e*) + f(t) x(t) =() e sin(26)g(t) g(t) = ( e sin(2t) + (t) y(t) = Ce+ sin(2t)) *g(t) 1
IV. Determine the form for yp but do NOT evaluate the constants. 1. y" - 5y' + 6y = ex cos 2x + e2x(3x + 4) sin x (ans. this is #21(a) in sec. 3.6) 2. y" - 3 y' - 4 y = 3 e2x + 2 sin x - 8eXcos 2x (ans. Yp = Ae2x + B cos x + C sin x + De* cos 2x + E e sin 2x) V. Solve by variation of parameters....
(2 points) Consider the following initial value problem, defined for t > 0: ' – 4y = f** (t – w) e4w dw, y(0) = -3. a. Find the Laplace transform of the solution. Y(s) = L {y(t)} b. Obtain the solution y(t). yt) =