Question

Suppose you a a mixture of 2-methyl-1-butene (20%) and 2- (30%) that equates to moles from 0.4 moles of 2 methyl-2-butanol, what is the percent yield of 20% b 40% C. 50% d. 80%
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Answer #1

Calculate 80% 2-methyl-2-butene of 0.2 mol asfollows: 0.2 mol 2-methyl-2-butene x 80%=0.16 mol 0.4mol of 2-methyl-2-butanol p

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Suppose you obtain a mixture of 2-methyl-1-butene (20%) and 2-methyl-2-butene (80%) that equates to 0.2 moles...
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