1)Let's say: Alphabets in the string={a,b}
And regular language be {a^n/n>0}
Therefore u={a^n/n>0}
|v|=2
Therefore v can be {aa,ab,ba,bb}
Since u is regular,v is also regular
we know that UV is also regular because a regular language is closed under concatenation
Therefore it proves that L1 is regular.
Hope it helps!
Comment below if any doubt.
Happy learning.
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