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3. (20 pt.) Prove that the following language is not regular using the closure properties of regular languages. C = {01|m,n

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Stept - Language Given is C=rom /m, n20 and mens V When we break this Language into 2 parts VL C = {oma/m, n2o and man} U cod Steb3 = Now, according to Closure boobooties of Languages c=4 ULZ CFL UCFL=CFL Hence, we can say that CFL is not regularRefer this closure properties table

Closure Properties REG DCFL RE CFL ✓ CSL ✓ REC ✓ ✓ X ✓ X ✓ ✓ X ✓ X ✓ х X ✓ Operations Union Intersection Complement Concatena

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