Question

Chapter 39, Problem 62. An unstable particle with mass m = 2.81 * 10 ^ -27...

Chapter 39, Problem 62. An unstable particle with mass m = 2.81 * 10 ^ -27 kg is initially at rest. The particle decays into two fragments that fly off along the x axis with velocity components u1 = 0.987c and u2 = -0.898c. From this information, we wish to determine the masses of fragments 1 and 2. (a) Is the initial system of the unstable particle, which becomes the system of the two fragments, isolated or nonisolated? [i.e. Are there external forces on the system?] (b) Based on your answer to part (a), what two analysis models are appropriate for this situation? [i.e. What two conservation laws are appropriate?] (c) Find the values of y for the two fragments after the decay. (d) Using one of the analysis models in part (b), find a relationship between the masses m1 and m2 of the fragments. (e) Using the second analysis model in part (b), find a second relationship between the masses m1 and m2. (f) Solve the relationships in parts (d) and (e) simultaneously for the masses m1 and m2.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

part a) isolated

part b )

Isolated system: conservation of energy, conservation of momentum.

part c )

y = 1/sqrt(1-(v/c)^2))

v = 0.987c

y1 = 1/sqrt(1-(0.987)^2) = 6.22

y2 = 1/sqrt(1-(0.898)^2) = 2.27

part d )

conservation energy gives E1 + E2 = Etotal

y1m1c^2 + y2m2c^2 = mc^2

6.22m1+ 2.27m2 = 2.81 x 10^-27 kg ...(1)

part e )

since the final momentum = 0

p1 = p2

y1m1u1 = y2m2u2

6.22 * 0.987c * m1 = 2.27 * 0.898c*m2

m2 = 3.012m1

put this in eq (1)

6.22m1 + 3.012m1 = 2.81 x 10^-27

m1 = 3.044 x 10^-28 kg

m2 = 9.168 x 10^-28 kg

Add a comment
Know the answer?
Add Answer to:
Chapter 39, Problem 62. An unstable particle with mass m = 2.81 * 10 ^ -27...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT