Question

Exercise 26.44 4 of 9 Constants A 12.0 uF capacitor is connected through a 0.890 MS resistor to a constant potential difference of 60.0 V. Part A Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 S. Express your answers using two significant figures. Enter your answers numerically separated by commas. VAJ O O ? 40:45.0: 910, 420, 9100 = Submit Request Answer Part B Compute the charging currents at the same instants. Express your answers using two significant figures. Enter your answers numerically separated by commas. IVO AQ R O 2 ? 10, 15.0, 110, 120, 2100 = Submit Request Answer

Answer 1

Here, C = 12 pF R = 0.89 Moh E = 60V Now, in RC charging circuit, the charge and current ean are given by - 8 = CE [1 – e-tre I = & et/Re I Part A We calculate, RC = 0.89x108x12x10-6 = 10.685 [ Time t=0 t = 5:05 t = los Charge 9 = ce[l-e"] = 0 9 = 12x10-6 +60 [1 - 2 - 3/10.68] 179= 2.69810-4 C 90 = 12 +10 - 6x60 [1 - é 10.68 172 = 4.38*10-4 e 420 = 12 +10 -6x60[1- e - 20 068 T = 6.09 4109 C 1910 =12x10-6. t=205 100 = 12 x106x60 [1 - e 10-18 = 7.199 810-40 t =loos

lime Current tos i = 60 se e ke = 6.74x18-S A t kos 5s in - 604 105 e/o = 4:22X10-SA t=10s . - 6.89 105 10 18 = 2-64105A [20 = 6 x 106 e 10 6 = 1:04 X10-SA 10 t=205 205 t=1805 / 400 = 0.89x105 et 10.68 - Eu tome