18-20 Please. Thank you. Solve the problem. 18) Assume that women have heights that are normally...
Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches. Write your answer as a decimal rounded to 4 places.
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If a woman is randomly selected, what is the probability that her height is between 58 and 80 inches?
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If 200 women want to enlist in the U.S. Army, how many would you expect to meet the height requirements? About 197 women
Question 25 5 pts Heights of adult American men are normally distributed with a mean of 69 inches and a standard deviation of 3 inches. Using the Empirical rule, approximately what percentage of men have heights below 63 inches? 68% O O O 95% 5% 2.5% Question 26 5 pts Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. Find the value of the quartile Q3. 66.1...
Assume that women's heights are normally distributed with a mean given by h = 63.7 in, and a standard deviation given by o = 3.1 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 63.6 in and 64.6 in. The probability is approximately (Round to four decimal places as needed.) b. If 20 women are randomly selected, find the probability that they have a mean height between 63.6...
Assume that women's heights are normally distributed with a mean given by u = 63.7 in, and a standard deviation given by o = 3.1 in. Complete parts a and b. a. If 1 woman is randomly selected, find the probability that her height is between 63.6 in and 64.6 in. The probability is approximately (Round to four decimal places as needed.) b. If 20 women are randomly selected, find the probability that they have a mean height between 63.6...
If the heights of women are normally distributed with a mean of 65.0 inches and a standard deviation of 2.5 inches and the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches, At 71 inches what is the probability for the height of a person of your gender to be within 3 inches of your height (between “your height – 3 inches” and “your height + 3 inches”)?
Solve the problem. 11) The amount of snowfall falling in a certain mountain range is normally distributed with a mean of 100 inches, and a standard deviation of 16 inches. What is the probability that the mean annual snowfall during 64 randomly picked years will exceed 102.8 inches? Estimate the indicated probability by using the normal distribution as an approximation to the binomial distribution. 12) A multiple choice test consists of 60 questions. Each question has 4 possible answers of...
In a population of 225 women, the heights of the women are normally distributed with a mean of 64.5 inches and a standard deviation of 2.9 inches. If 25 women are selected at a random, find the probability that their mean height will exceed 66 inches. Assume that the sampling is done without replacement and use a finite population correction factor with N=225. Pls. show solution
the heights of women aged 18-24 are normally distributed with mean 64.5 inches and a standard deviation of 2.5 inches. Let X denote the height of a woman. Based on the empirical rule (68-95-99.7rule) answer the following a) P(X<62 or X>69.5)=?