If the heights of women are normally distributed with a mean of 65.0 inches and a standard deviation of 2.5 inches and the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches, At 71 inches what is the probability for the height of a person of your gender to be within 3 inches of your height (between “your height – 3 inches” and “your height + 3 inches”)?
If the heights of women are normally distributed with a mean of 65.0 inches and a...
Heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. What is the probability that a randomly selected group of 16 men have a mean height greater than 71 inches.
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If a woman is randomly selected, what is the probability that her height is between 58 and 80 inches?
Men’s heights are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. a) What is the probability that a man selected at random is at least 72 inches tall? Round the answer to 4 decimal places. b) The Mark VI monorail used at Disney World has doors with a height of 72 inches. What doorway height would allow 98% of adult men to fit without bending?
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If 200 women want to enlist in the U.S. Army, how many would you expect to meet the height requirements? About 197 women
Assume that the heights of men are normally distributed with a mean of 68.1 inches and a standard deviation of 2.8 inches. If 64 men are randomly selected, find the probability that they have a mean height greater than 69.1 inches
Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches. Write your answer as a decimal rounded to 4 places.
2) The heights of men are normally distributed with a mean of 68.6 in and a standard deviation of 2.8 in. The heights of women are normally distributed with a mean of 63.7 in. and a standard deviation of 2.9 in. a) Find the 90th percentile of the heights of women. b) Which of these two heights is more extreme relative in the population from which it came: A woman 70 inches tall or a man 74 inches tall? Justify...
Men’s heights are normally distributed with a mean of 68.5 inches and standard deviation 2.2 inches. The U.S. Navy requires that fighter pilots have heights between 62 in. and 78 in. If the Navy changes the height requirements so that all men whose heights fall within the middle 82% of the population are eligible to be fighter pilots, what are the new requirements for men? Please show all your work and write your answer in a complete sentence. (7 points)
1. [1+1] If the heights of women are normally distributed with a mean of 64 inches, which of the following is the highest? The probability of randomly choosing (A) one woman and finding her height is between 63 and 65 inches. (B) 15 women and finding that their mean height is between 63 and 65 inches. (C) 100 women and finding that their mean height is between 63 and 65 inches. (D) all of the above have the same probability....
the heights of women aged 18-24 are normally distributed with mean 64.5 inches and a standard deviation of 2.5 inches. Let X denote the height of a woman. Based on the empirical rule (68-95-99.7rule) answer the following a) P(X<62 or X>69.5)=?