Question

" U pts.) A horizontal curve links two roadway tanrents that deflect at 40 degrees. It is degree curvature equals 6, answer the below questions. 1. What is the curve's radius? (1 pt.) 2. What is the length of curve? (1 pt.) 3. What is the length of the long chord? (1 pt.) Select a station for the curve's Pl and answer the below questions. 4. What is the station of the PC? (1 pt.) 5. What is the station of the PT? (1 pt.) 6. Provide the chord to the previous station and the total deflection angle to the first whole station on the curve. (2.5 pts.) 7. Provide the chord to the previous station and the total deflection angle to a whole station of YOUR choice on the curve. (2.5 pts.)

Answer 1

solution: 31) Assuming 30 m chain: D = 1720 R 36= 1720 = 286-67 m) Assuming zom chain DP 1146 R$ 1946 = 1914 TR 191m] K - 191m V90 261 26° for mx {R=1914} 360 de 2TR x40 = 133.34 m Ll= 133.34 m)

3 Length of the long Chord EL L = 2 RSin 20 TL - 130-65m) 0 Station of pc = Station of PI Where T = Rtan 20 T = 191tanzo T= 69.52m I Hence Station of P (= station of pl -69.52m 5 Station of PT= Station of PI+ 69.52