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HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24...
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1...
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1 ft and a deflection angle of 40°. The point of curvature (PC) of the curve is at sta 457+38.5. (The information is applicable to Problems 5 through 6). PI 40° sta 457+38.5 PC PT C . Based on the above illustration, what is the radius (R) for this curve? (2pts)
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI...
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI Station: 12+40.00 R-572.96 feet Deflection angle A-12.30 What is the Station of PT? PI PC PT Part B. An existing highway has a historic site located at the PT of an existing curve with a PI located at Station 80+00, an extemal angle of 65°, and a radius of 1,200 ft. The curve must be relocated, moving the PI to Station 78+00. The external...
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is...
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 1...
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 14+67.21; a. The curve length for the above horizontal curve b. With a theodolite on the BC, what is the deflection angle from PI to station 16+50? c. What is the chord length from station 15+50 to 16+50? d. Holding the PI at the same point, if the radius of the above was changed to 900 ft, what would the new BC stationing...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Name: Grade: /10 Dec 3, 2018 w ..CA-Horizontal Curve VI FORT WAYNE Tabulate R or D,...
Name: Grade: /10 Dec 3, 2018 w ..CA-Horizontal Curve VI FORT WAYNE Tabulate R or D, T, L, E, M, PC, PT, deflection angles, and incremental chords to lay out the circular curves at ful stations (100 ft) for the Highway curve with R 1200 ft, I-30°00, and PI station 45+ 50.00 ft. Station Chord Defl. Increment Defl. Angle
4. In the horizontal curve for the spine road in your development, the entering tangent is...
4. In the horizontal curve for the spine road in your development, the entering tangent is at Azimuth or True North Bearing of 210°、The leaving tangent is at 165°. The coordinates of the PI are N 2,000; E 3,000. The PI is exactly 1,200 ft. from point B, the beginning of the Route from the intersectionl. This beginning point is at station 0+00. The radius of the curve İs 600 ft. B- AZ 210 FIND THE FOLLOWING for the curve:...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T=...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T= 229.27 ft and an arc length L 391.53 ft. If the station of the PI is established as 7 +47.64, find the stations of the PC and the PT
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane...
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of Pl: 2700+10.65 fs- 0.12 e- 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station. 15-11. A proposed highway has two tangents of bearings N...
Referring to the following illustration, a circular horizontal curve has a chord length (C) of 1710.1 ft and a deflection angle of 40°. The point of curvature (PC) of the curve is at sta 457+38.5. (The information is applicable to Problems 5 through 6). PI 40° sta 457+38.5 PC PT C . Based on the above illustration, what is the radius (R) for this curve? (2pts)
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI Station: 12+40.00 R-572.96 feet Deflection angle A-12.30 What is the Station of PT? PI PC PT Part B. An existing highway has a historic site located at the PT of an existing curve with a PI located at Station 80+00, an extemal angle of 65°, and a radius of 1,200 ft. The curve must be relocated, moving the PI to Station 78+00. The external...
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
1. Given the following horizontal curve data, answer questions a d. R-800 ft, 30°. BC Station Δ 14+67.21; a. The curve length for the above horizontal curve b. With a theodolite on the BC, what is the deflection angle from PI to station 16+50? c. What is the chord length from station 15+50 to 16+50? d. Holding the PI at the same point, if the radius of the above was changed to 900 ft, what would the new BC stationing...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Name: Grade: /10 Dec 3, 2018 w ..CA-Horizontal Curve VI FORT WAYNE Tabulate R or D, T, L, E, M, PC, PT, deflection angles, and incremental chords to lay out the circular curves at ful stations (100 ft) for the Highway curve with R 1200 ft, I-30°00, and PI station 45+ 50.00 ft. Station Chord Defl. Increment Defl. Angle
4. In the horizontal curve for the spine road in your development, the entering tangent is at Azimuth or True North Bearing of 210°、The leaving tangent is at 165°. The coordinates of the PI are N 2,000; E 3,000. The PI is exactly 1,200 ft. from point B, the beginning of the Route from the intersectionl. This beginning point is at station 0+00. The radius of the curve İs 600 ft. B- AZ 210 FIND THE FOLLOWING for the curve:...
Example 10-5 Consider the simple horizontal curve given in Example 10-1, with a tangent distance T= 229.27 ft and an arc length L 391.53 ft. If the station of the PI is established as 7 +47.64, find the stations of the PC and the PT
6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of Pl: 2700+10.65 fs- 0.12 e- 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station. 15-11. A proposed highway has two tangents of bearings N...
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