Homework Answers
Given,
Tangent distance, T = 229.27 ft
Length of curve, L = 391.53 ft
Station of PI = 7 + 47.64
Station of PC = Station of PI - (L/2) = (7+47.64) - (1+95.77) = (5+51.87)
Station of PT = Station of PI + (L/2) = (7+47.64) + (1+95.77) = (9+43.41)
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