Question

For a horizontal curve, the back tangent azimuth is 271 10 37 and the forward tangen azimuth is 51 1515 and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the PI to the RP?

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For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is...
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