ZuoTi.Pro
Question

For a horizontal circular curve, the back tangent is S11 4117E tangent is N79°1111E. The curves radius is exa sketch of the curve. Compute the curve parts delta, L, LC, E, M and T. Whats the area of the figure bounded by the two tangents and the long chord? and the forward ctly 5000.00 feet. Draw a scaled

engineering   Civil-Engineering   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

LC 2 Δ 89°132, = 360 360 ε 구구子子·642 ft 子016 .9 ft

0 0
Add a comment
Know the answer?
Add Answer to:
For a horizontal circular curve, the back tangent is S11 41'17"E tangent is N79°11'11"E. The curve's radius is exa s...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24...

    HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24°00" PI @ Sta. 64+27.46 Dare = 20000" Coordinates of the PI are 1234.56N & 2468.10E R 2864.79 ft The Azimuth of the back tangent is 76 26'30" T = 210.38 ft. (Azimuth from PC to PI) L =420 ft. Draw a sketch and calculate the following: a) The station of the POC b) The coordinates of the PC c) The station of the PT...

  • For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is...

    For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the...

  • 6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane...

    6:47 1 4 Search <Back Hw#3-2019.doc 15- 10. A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of Pl: 2700+10.65 fs- 0.12 e- 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station. 15-11. A proposed highway has two tangents of bearings N...

  • Show all work please. ECC 310 In Class Assignment Curves/Coordinates 10/31/2018 Problem: A horizontal highway curve...

    Show all work please. ECC 310 In Class Assignment Curves/Coordinates 10/31/2018 Problem: A horizontal highway curve has a radius of 567.23 feet, delta angle of 43-24-54, bearing from C to PC of N 22-17-45 W and coordinates at C N 5000.00 E 5000.00 and station of PI- 10+00.00. Draw a sketch of the curve and determine the stationing and coordinates of the PC, PT, Pl and dimensions of all curve components.

  • ON2ohtal curves .The deflecti n angle used when sighting back on the curve during a move up was w...

    Please complete the chart and explain how to solve number 16. Thank you. oN2ohtal curves .The deflecti n angle used when sighting back on the curve during a move up was wrong, causing the curve to get wasn't enough, and the construction equipment removed the stakes. Using the wrong backsight when laying out a curve by QUESTIONS AND PROBLEMS Calculate the missing curve parts in the following Table. Curve# 1 of Curve E M.O. LC 1 18°54' 357.25 2 2930...

  • Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of...

    Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale

  • 1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30°...

    1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30° Rt. D = 5° Design Speed = 50 mph Two lane road in Southern Climate PI Station @ 64+20.00 Find Land e from Table 13.8 or 13.9 (see handouts) Compute: As = Ac Y Xs es = R= P= TS Compute the stations of: T.S. = S.C. = C.S. = S.T. = Compute the Long Tangent and the Short Tangent Spiral Curve Equations Spiral...

  • 1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30°...

    1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30° Rt. D=50 Design Speed = 50 mph Two lane road in Southern Climate PI Station @ 64+20.00 Find and e from Table 13.8 or 13.9 (see handouts) Compute: R P= Compute the stations of: T.S. = S.C. = C.S. S.T. = Compute the Long Tangent and the Short Tangent PI 4 CPI To AC ST To S.C. C.S. SPI, SPI -Ls 20$ Cc 3...

  • no you dont. let someone else answer it. 1. Given the following horizontal curve and spiral...

    no you dont. let someone else answer it. 1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30° Rt. D= 5° Design Speed = 50 mph Two lane road in Southern Climate PI Station @ 64+20.00 Find and e from Table 13.8 or 13.9 (see handouts) Compute: = R P= Compute the stations of: T.S. = S.C. C.S. = S.T. = Compute the Long Tangent and the Short Tangent Table 13.9 SPIRAL CURVE LENGTHS...

  • Problem 1 (15vpts) A proposed highway has two tangents of bearings N 75° 54' 36" E...

    Problem 1 (15vpts) A proposed highway has two tangents of bearings N 75° 54' 36" E and N 53° 22' 30" W. The highway design engineer, attempting to obtain the best fit for the simple circular curve to join these tangents, decides that the external ordinate is to be 78.00 ft. The Pl is at station 65+43.21. Determine: (a) The external angle of the curve (A) (b) The radius of the curve (d) The station of the PC (f) The...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT