Question

1. Given the following horizontal curve and spiral data: Total tangent deflection angle (A) = 30° Rt. D= 5° Design Speed = 50 mph Two lane road in Southern Climate PI Station @ 64+20.00 Find and e from Table 13.8 or 13.9 (see handouts) Compute: = R P= Compute the stations of: T.S. = S.C. C.S. = S.T. = Compute the Long Tangent and the Short Tangent

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Answer 1

0 Two lane Road in Soutbren Climate A = 30° D=5° Design Speed - 50 mph PI Station @ 64 + 20.00 From Table 13.8 For a lone Road R = 1146' Ls a 200 e=0.083 200 X5 Spiral Tangent Deflection Ag2 As -5° Total Deflection Az Act 2 As 200 200 Ac = 4-2A8 = 30°-285 = 20° Ac 520° 3 - 5.817 GRLs 6x1146x 200 Ys = 483 (2001 X = L₂ Cosos Os - -1.67 Xg 200x Cos 1.67' - 199.91 R = 1146' From Table 13.8 P = Y-R (LCOSA) = 5.817 - 1146(1-6055 P = 5.817 – 4.361 = 1.456' P=1456 To = X-R Sin A, + (R+P) Tan = 200 - 1146 Sisst (1146+1.456) Tan & To = 150.218 2

To state = TS station PI- Is = 6420' - 150.218 = 6269.782 TS station = 6269.782 = 6269,782 +200 Sc Station 2 6469.782 Cs station - Scotat Le L - Lc+2Ls hat Lc = 2R SID 4 = 2x1146 Sis 30 Lc=593.213 Cso station = tha - Segta 6469.782 +593.213 cs station = 7062.99 ST station = CS sia Caths = 7062.99 + 200 7262.99 . ST Station a 7262,99 Long Tangent LT = x- y tan A, 5.817 199.9) = 199.91-66.488 Tango - Long Tangent LT = 133.421' Ys 5.817 Short Tangent ST = Sin As Tin5° - 66.743 - Short Tangent ST = 66.743'

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