Question

Two radio antennas separated by d = 290 m as shown in the figure below simultaneously broadcast identical signals at the same wavelength. A car travels due north along a straight line at position x = 1140 m from the center point between the antennas, and its radio receives the signals. Note: Do not use the small-angle approximation in this problem. d F------ (a) If the car is at the position of the second maximum after that at point o when it has traveled a distance y = 400 m northward, what is the wavelength of the signals? 23.9 Return to the derivation of the locations of constructive interference in Young's double slit experiment. m (b) How much farther must the car travel from this position to encounter the next minimum in reception? m

Answer 1

given that daagom two radio antenna position n = 114om : ro [n=2] a) y for y= 400 11 frem fig tano y Botanto) = tanto the 10= 19.33º ] As we know dsino and da asino - 290xsin 119.83) 2 da 47.99 na 48m 1 b) distance transelled by car asino = (n + ) + sino a 12+1/2 t. W sx48 ago 0 : Sinit(0.413) To= 24.44 tanos y

y'= a tano 11 40 tan (24-44) ul = Tyl 51849 Ay=.9'-y = 518-400 = 118m Ay= 118m so car to has to travell extra 118m minimum in recephon en counter ext