Question

IH the figure the following values are given FCV DCV PRV Pump: Vo 6 in2: n 0.92; m 0.95; Np-1,500 RPM Motor: Vo= 8 in": 0.90; n-:0.93 Oil: v=100 cS; SG= 0.90 FCV: Cv 0.2 gpm/psi2, Apcomp 120 psi Pipes (schedule 80): Pipe No. Length [ft] N a) Describe the component labeled FCV and the full Diameter [in] functionality of the system (10p). 1.25 10 b) Determine the angular velocity of the motor M for CW 1(left DCV envelope) and Ccw (right DCV envelope) directions. Show values in RPM (20p). c) Calculate the actual torque (use inlb) produced by the motor for CW rotation. Consider the pressure losses due to friction. The pipes are Schedule 80 steel pipes, the line corners in the schematic correspond to 90° elbows (K=0.75) and the PRV valve is connected to the main pipe with a standard tee (K-18), The strainer and the DCV have K factors of 3 and 10 respectively. The PRV is set to open at 2.000 psi.(30p) d) What is the overall efficiency of the system? (10p)

Answer 1

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