Question

Determine the reactions at the smooth support A an
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Answer #1

The Cantilever beam is loaded upon by Uniformly Distributed Load with free end resting on a wedge of 60 degrees.

The intensity of UDL, w = 150 lb/ft.

The length of the beam, l = 10 ft.

Lets assume fixed end to be x = 0 and free end to be x = l

Consider any cross-section XX which is at a distance of x from the fixed end. If we just take the resultant of all the forces on the right of the X-section, then

S.Fxx = -W(l-x) for all values of ‘x'. ---------- (1)

S.Fxx at x=0 = -Wl

S.Fxx at x=l = 0

So if we just plot the equation No. (1), then it will give a straight line relation. Bending Moment at X-X is obtained by treating the load to the left of X-X as a concentrated load of the same value acting through the centre of gravity.

Therefore, the bending moment at any cross-section X-X is

B.Mxx = -Wl * (l-x)/2

B.Mxx at x =0 = -Wl2/2

B.Mxx at x =l = 0

So, the reaction at point B i.e. the fixed end will be equal to the shear force, -Wl = -(150)*10=-1500 lb.

The reaction (shear force) at free end will be zero and hence reaction at point A i.e. the frictionless smooth point will also be zero.


X-X x-0

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