Question

(35 polnts) An engine hoist is shown below. Joint A ls a smooth frletionless pin connection. Memher BC contains the hydraulie cylinder. BC is pinned to ACD at C witha smooth frietionless pin. Assume that BC ls a 2-force member. The mass is suspended from D with a cable. Solve for the reaction(s) at A, C, and D (5 points) . Do first Part oly 2.00 0.50 1.00 2.00 250. kg 2.50 Distances m

Answer 1

250(9.81) = 2452.5N sigma M_A = 0: F_BC(1/1.12)(0.5)-2452.5(2) = 0 F_BC = 2452.5(2)(1.12)/0.5 F_BC = 10987.2N sigma F_Y = 0: A_y + 2452.5-10987.2(1/1-12 = 0 A_y = 7357.5N downarrow sigma F_x = 0: A_x = 10987.2(0.5/1.12) A_x = 4905N leftarrow C_x = 4905N rightarrow C_y = 10987.2(1/1.12) C_y = 9810N uparrow