9) The reaction 2C-D + E (K= 3.3 x 10-3) has [C]-0.05 M and [DHE]-5 x...
2. For the reaction: A(g) +B(g) = 2C(g) K = 1.0 x 10-5 at 25°C When equilibrium was reached at 25°C, the equilibrium concentrations of the reactant gases were: [A] = 2.5 x10-2M [B] = 2.0 x 10- M Calculate the equilibrium concentration of the product gas C? 3. At a certain temperature the reaction has an equilibrium constant of 0.400. CO(g) + H2O(g) = CO2(g) + H2(g) When 1.50 mol of carbon dioxide gas and 1.50 mol of hydrogen...
consider the reaction A+B<----->C+D, which has an equilibrium constant K, equal to 3.4 x 10^2 1. If one begins a reaction by placing 0.6000 moles of A in 1.0 L container as well as 0.150 moles of B, what will be the equilibrium concentrations of A, B, C, and D? 2 Once the reaction in problem one reaches equilibrium, some additional B is injected into the flask from an outside source. LeChatelier's principal says the reaction will be a) unchanged...
The equilibrium constant () of the reaction below is K-6.0 x 10 with initial concentrations as follows: [H2] = 1.0 x 102 M. [Na] - 4.0 M, and (NH) - 1.0 x 10* M. N (8) + 3H,() 2NH3(e) 3. Consider the chemical reaction: N2 + 3H2 yields 2NH3. If the concentration of the reactant Hy was increased from 1.0 x 10-2M to 2.5 x 10-M, calculate the reaction quotient (C) and determine which way the chemical system would shift...
For the diprotic weak acid H2A, K.1 = 3.3 x 10-6 and K 2 = 7.1 x 10-9 What is the pH of a 0.0550 M solution of H,A? pH = What are the equilibrium concentrations of H, A and A?- in this solution? [H, A] = [A?-) =
3) The reaction below has a Kc value of 3.64 x 10-3. What is the value of Kp for this reaction at 25°C? 2 NaN3(s) - 2 Na(s) + 3 N2(g) A) 131 B) 53.2 C) 8.90 x 10-2 D) 29.9 E) 0.613 5) Determine the value of Ke for the following reaction if the equilibrium concentrations are as follows: [N2 Jeq - 3.6 M, [O2 Jeq - 4.1 M, [N20Jeg - 3.3 * 10-18 M. 2 N2(g) + O2(g)...
help please 1-4 consider the reaction A+B 3 C + D. which has an equilibrium constant, K, equal to 3.4 x 10. 1. IT one begins a reaction by placing 0.600 moles of A in a 1.0L container as well as 0.150 moles on , what will be the equilibrium concentrations of A.B.C. and D? Write your answers in the spaces provided below. a. (A) = b. [B]= = C. (C)= d. (D)= 2. Once the reaction in problem 1...
Page Chp 14 28. This reaction has an equilibrium constant of K,- 22 x 10 at 298 K 2COFg)CO(g)+CFA Calculate K, for each reaction and predict whether reactants or products will be favored at equilibrium. An equilibrium mixture of this reaction at a certain temperature has INH,J- 0.278 M and [H S]- 0.355 M. What is the value of the equilibrium constant (K) at this temperature? 66. Consider this reaction at equilibrium: 60. Consider the reaction Predict whether the reaction...
10) The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 10) 2 SO2(8) + O2(8) - 2 SO3(3). If initial concentrations are [SO2) = 6.00 M, [02] -0.45 M, and (SO3) = 9.00 M, the system is A) not at equilibrium and will shift to the right to achieve an equilibrium state. B) not at equilibrium and will shift to the left to achieve an equilibrium state. C) at equilibrium D) not at equilibrium and will...
________________________________________________________________________ The reaction 3A(g)B(s)2C(aq)D(ag) occurs at 25°C in a flask, which has 3.01 L available for gas. After the reaction attains equilibrium, the amounts (mol) or concentrations (M) of substances are as follows: 6.13 mol A, 2.37 M C 1.90 mol B, 3.10 M D What is the equilibrium constant Ke for this reaction at 25°C? You place S.49 mol of dinitrogen trioxide, N2O3, into a flask where it decomposes at 25.0°C and 1.00 atm N203 (9)NO2(g) NO(g) What is...
A Q=K: the reaction mixture is at equilibrium O T OM B. Q<K; the reaction will shift towards the reactants C. Q>K; the reaction will shift towards the products → KA А е е D. Q>K; the reaction will shift towards the reactants MOL (E. Q<K; the reaction will shift towards the products. M280. 00 3. For the reaction M SES00.0 3 to noiriwa H2 (9)+CO2(9) <==> H20 (9) +CO (9) Kc = 0.798 at 320°C. 0.492 moles of H2...