1) If I is the intensity of sound,
then,
sound intensity level, beta = 10*log(I/Io)
0 = 10*log(I/10^-12)
0 = log(I/10^-12)
10^0 = I/10^-12
1 = I/10^-12
I = 10^-12
so, o dB means Intensity of sound is 10^-12 W/m^2
2) Yes. negative decible means the sound intensity is less than 10^-12 W/m^2 which can not be heard by human year.
3) given I2 = 2*I1
difference between sound intensity levels,
beta2 - beta1 = 10*log(I2/Io) - 10*log*(I1/Io)
= 10*log(I2/I1)
= 10*log(2*I1/I1)
= 10*log(2)
= 3.01 dB
4) if distance is doubled intensity becomes 1/4 times
I2 = I1/4
beta1 - beta2 = 10*log(I1/Io) - 10*log*(I2/Io)
= 10*log(I1/I2)
= 10*log(I1/(I1/4))
= 10*log(4)
= 6.02 dB
so, the sound intensity level reduces by 6.02 dB
Sound Level Workset Name Sdverstone PH105 Spring 2018 Show all math stops and write wnis wi...
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