A 2.5-cm-tall object is 90cm in front of a diverging lens that has a -45cm focal length.
A) Calculate the image position.
B) Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted.
Please show all your formulas and work!
given are
ho=2.5cm
d0=90cm
f=-45cm
using lens formula
1/f=1/d0+1./di
1/-45=1/90+1/di
1/di=1/90+1/45
1/di=0.033
di=30.3 cm
Magnification: M = -di/do
=30.3/90
=0.336
M=hi/ho
0.336=hi/2.5cm
0.336*2,5=hi
0.841cm=hi
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