Question

A 3.0-cm-tall object is 24 cm in front of a diverging lens that has a -30 cm focal length. 1. Calculate the image position. 2. Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted.

Answer 1

-1/f = 1/Di + 1/Do

-1/-30 = 1/Di + 1/24

Di = -120 cm

M = Di/Do = -120/24 =-5

as magnification = image height / object height = hi/ ho
m= hi/ ho

So, -5 = hi/3

or hi = -15 cm

inverted