1)
a) AlCl3 is a strong Lewis acid and will acquire the Cl from the solution mixture. This will make the remaining electron deficient part of the molecule to attach the electron-rich sulfonated benzene ring. The presence of Oxygen groups in the sulfate molecule results into -I effect and thus decreases the electron density of the ring making the ring a Meta directing entity. Hence the incoming electrophile will attack at the Meta position.
b) Nitration of phenol. As phenol is electron donating group, it is an ortho-para directing entity and the electrophile (i.e NO2+ ) will attack those specific positions only. The para substituted product will be the major product due to the extra stability. In case of ortho-substituted product due to electronic repulsions of the neighboring groups, the molecule is bit unstable.
c) As the para position is already taken up by the Methyl group the sulfate will have to attach on ortho position itself. No other position is possible.
1. Fill in the missing reactants, reagents & conditions, or products. Indicate major product only, unless...
2. Fill in the missing reactants, reagents & conditions, or products. Don't worry about stereochemistry, unless indicated. OH NaBH4, MeOH H' cat NaBH4, MeOH ме
2. Fill in the missing reactants, reagents & conditions, or products. Don't worry about stereochemistry, unless indicated. 1. LDA, -78c OCH then H3o 0 CO Et H3o C10H100 CH NaOEt (aq) 0 0 NaOH (aq) NaOEt (aq) 0
Question 6, Contd... Provide the missing major organic products or reagents/conditions for the following reactions. Unless indicated otherwise, do not forget to include stereochemistry as appropriate and INDICATE ANY RACEMIC MIXTURES. OCH3 1 Equiv. CH3NH2 ignore stereochemistry NMez HCI (cat.) heat excess 1. Nat OEt OEt Eto OEt excess 2. H3O+ Ph
Queston 6 (56 pts.). Provide the missing major organic products, or reagents/conditions, or organic reactants, as appropriate. Do not forget to include stereochemistry as appropriate unless specified otherwise. 2. Hgo :0: :o 1. Na* CN 2. H30* /heat gnore stereochemistry c) :Br: :OH d) 1 Equiv H3C CI: e) Ph h) heat (Aldol reaction)
Please Pr 2. Fill in the missing reactants, reagents & conditions, or products. Show stereochemistry where appropriate. 10 points. excess MgBr OH Me then H20 Ph3P OMe NH N﹀Me MeO MeO
Please Print! 2. Fill in the missing reactants, reagents & conditions, or products. Show stereochemistry where appropriate. 10 points. MgBr OH then H30+ „CH₃ HAN CH3 Ht cat MgBr N-CH₃ Мео (then H30t Meo он NaCN -CH3 CH₃ OTS CN or CH "CH₃ +
Fill in the missing reactants, reagants, and conditions, or products. draw both possible products Br2 Me CO2Me Me CO2Me
NAME! Please Print! 4. . Fill in the missing reactants, reagents & conditions, or products in the following road map. Show stereochemistry where appropriate. 10 points. CH3 AICI: CH₃ (но CH3 AICI: CH,CI NO2 Brmg then H,07
8. Predict the major product or products for the following reactions. Assume reagents are present in excess amounts unless otherwise indicated. Clearly depict any stereochemistry. "No Reaction is a possible answer. (4 points) each So, H2SO4 CH,CH,C1 AICI, NO Br2 FeBry OH 어 CI AICI, FeB NOH 100 °C 2.HO die HCI HO
5. Complete the following reactions by filling in the missing Reactants, Reagents, or MAJOR Product. If TWO products are equally formed show BOTH. 1. DIBAL 2. H307 Colon - ohne кон ОН OH NH2 LIAIH4 1. LDA / Dry THE - to 1.LA/D THE 1.1.2 Equiv. LDA/THF 2. Br Br2 acetic acid Pyridine Heat Nat Et EtOH single product