Question

Перо Name _Date Section 1. mass of aluminum 16.2058 2. mass of alum possible (theoretical yield) 3. mass of alum produced (actual yield) 4. percent yield Show calculations by number:

Answer 1

@: 0 Molarity - Mole Politie rolume Mole = Molarity & Volume. (Malleuson = 1.403 M* C.COM) = 0.07024821 mole. (Mo) Gavion = 159.609 Hool 159.609 g/mol Massason = Molex Molas Mass 0.07024821 mol X 159.609 91.. 55.7 gm of I gm of Brg in Cubra in 100 mL of water 100 mL of water 5 5.7 P or: 55.7 9 i Tom = . 0.557 Eli is solubility in Jaturated Solution. 100 - Given Sample: 180 gm - 0.514285 gm 음 350 ~ is In Giren Sample less amount of salt dissolved per mL in Saturated solution. CNo ppt will form) . would not . -

- formula of Alum: K AI (son) lango - Mass of Al = 27 g/mol (Mole) = 0.205 g 27 g/mol 0.0076 mole from 1 mol of Alumis Al O 1 1 mole of producted Al atom) (Both have oles of Alum formed= 0.0076 mol (Molas Marshalom = 474• 39 g/mol Mans of Alum formed = Mole) Molar Mars -0.0076 mol x 474. 39 g boli = 3.60 gm Theoritica Mas produced % yield= Actual yield Theoritical yield x 100. Y. 63 g 3.60 gm 100% - 173%