Two forces acting on an object have magnitudes F1 6.6 N and F2 2.2 N. Which...

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Question

Answer 1

Answer #1

here,

F1 = 6.6 N (- i)

F2 = 2.2 N ( j)

let the third force required be F3

as they are in equilibrium

F1 + F2 + F3 = 0

- 6.6 N i + 2.2 N j + F3 = 0

F3 = 6.6 N i - 2.2 N j

the magnitude of force , |F3| = sqrt(6.6^2 + 2.2^2) = 7 N

the direction of force , theta = arctan((-2.2)/6.6) = 162 degree counterclockwise from F1

so the correct option is &)

Answer 2

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