a] The capacitance of a capacitor is given by:
k = dielectric constant
d = distance between the plates and A = area of the plates
so, the capacitance for this circular capacitor will be:
C = \frac{\epsilon_o \pi r^2}{d}
b]
From Ampere's law,
\int B.dl = \mu_o I = \epsilon_o \mu_o \frac{d\phi_E}{dt}
and the electric flux is the product of electric field and the area
so,
I = \epsilon_o \pi r^2\frac{dE}{dt}
so, the rate of change of electric field will be:
\frac{dE}{dt}= \frac{I}{\epsilon_o \pi r^2}
a) A capacitor is made of two circular plates of metal with radius r separated by...
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