(+30) You have a half-filled hot tub that is cold (T-25 "C). You have two ways...
A hot tub is filled 450 gallons of water. a. What is the volume of water in liters in the tub? b. What is the mass in kilograms of the water in the tub? c. How many kilocalories are needed to heat the water from 69 degrees Fahrenheit to 204 degrees Fahrenheit? d. If the hot tub heater provides 5900 kJ/min, how long in hours will it take to heat the water in the hot tub from 69 degrees F...
Problems 1. The following equation describes the process of warming a hot tub by adding hot water: IN-ISTART) where is the temperature of the water in the hot tub is the temperature of the water flowing into the hot tub, (130°F) is the initial temperature of the water in the hot tub (65°F) is the hot-water flow rate (5 gpm) is the volume of the hot tub (500 gallons), and is the elapsed time since the hot water started flowing...
Hot Water Heater Due in 7 hours, 27 minutes A family comes home from a long vacation with laundry to do and showers to take. The water heater has been turned off during vacation. If the water heater has a capacity of 51.8 gallons and a 4610 W heating element, how much time is required to raise the temperature of the water from 22.0°C to 64.9°C? Assume that the heater is well insulated and no water is withdrawn from the...
Your house has lost electricity and natural gas. Luckily, you still have running water but the idea of an ice cold shower doesn’t appeal to you. So you want to have a hot water bath but the only source of heat is a wood fire. You put 195L of cold water (15C) into the tub but you are going to have to carry something hot from the fireplace to the tub to heat it up. You have two choices. You...
Piece #3 (1 pt): I put an ice cube in my soda. If the ice cube gains 1000 J of heat, how much heat does the soda lose? Piece #4 (1 pt): How much energy would be required to raise the temperature of 1.00 kg of water from 20°C to 45°C? Piece #5 (1 pt): How much electrical energy would I need to raise the temperature of 1.00 kg of water from 20°C to 45°C if my heater was only...
To cool her 0.200 kg cup of 75.0 C hot chocolate (mostly water), Heidi drops a 29,.97 g ice cube at 0 C into her insulated cup. After the ice cube melts, the temperature of the hot chocolate comes down to 54.8 C. a. How much energy was lost by the hot chocolate? The specific heat capacity of water is 1 cal/g C b. How much energy was gained by the ice cube just to melt to 0 C water?...
You pour 210 g hot coffee at 78.7 degree C and some cold cream at 7.50 degree C to a 115-g cup that is initially at a temperature of 22.0 degree C. The cup, coffee, and cream reach an equilibrium temperature of 63.0 degree C. The material of the cup has a specific heat of 0.2604 kcal/(kg middot degree C) and the specific heat of both the coffee and cream is 1.00 kcal/(kg middot C). If no heat is lost...
you have a 6 volt battery connected to a heating wire. the heating wire is placed in 100 gram of water( in a perfect insulator). the heater runs for 55 seconds. during this time, the water increases in temperature by 22 degree Celsius. if the specific capacity of the water is 4.186 joules/g*c, how much current flow from the battery? assume there are no energy losses?
Suppose you used a hot pot to convert a 150 g piece of ice that was initially at -15°C into liquid water at 50°C. a) Represent this process in one complete energy-system diagram covering the entire interval. b) How much heat is added to complete this entire process?c) If your hot pot has a power rating of 600 watts, show how to find how long it will take to complete the process. (Make sure you are comfortable using standard units of energy, and...
Question: A kettle holding 1.18 L of water at T, 16.7 C is switched on. The kettle uses P 1286 W of electricity. The latent heat of vaporization is L 2.26 x 10Jkgwhile the latent heat of fusion is L3.33 x 10 Jkg Part 1) How much energy is required to increase the temperature of the water to 100 C? Q = Part 2) If the kettle is 100% efficient, with all the supplied power going into heating the water,...