A rectangular channel with slope So = 0.005, n = 0.015. The width is b = 4.0 m and discharge in the channel is Q = 12.0 m/s. If the water depth at a given section along the channel is y: = 0.92 m, determine the distance from the section where the flow depth reaches the normal depth (14 marks). Explain your solution, showing your results in a clearly labelled sketch (6 marks).
Q1. For a uniform flow, a trapezoidal channel has a base width b = 8 m and side slopes 11:1V. The channel bottom slope is so = 0.0002 and the Manning roughness coefficient n = 0.016. Compute a) The depth of uniform flow if Q = 14.3 m3/s b) The state of flow. yo У. b= 8 m
Problem #2 Water tank is supplied with water at a flow rate Q = 0.005 m/s. A 5 cm diameter, 15 m long pipe is attached to the tank at the bottom and discharges to the atmosphere as shown in the figure. The pipe has roughness e = 0.0015 mm and the water is at 18°C. Answer the following: a) If the depth of water in the tank is initially 7 m, does the amount of water in the tank...
Question 6 A concrete-lined trapezoidal channel with uniform flow has a normal depth of 1.5 m. The base width is 4 m and the side slopes are equal at 1 vertical to 2 horizontal. Mannin‘s n-0015. The bed slope 0.001 Compute the mean velocity and discharge. If the above channel were to be designed for flooding, it may have a section like in Figure below 8 m 8 m 4 m When the flow goes over the top of the...
Determine the flow velocity (ft/s) a most hydraulically efficient trapezoidal channel (m=2) would be designed to carry water on a slope of 0.0015‐m/m excavated in coarse gravel with D75 of 1.2‐in (n=0.03). Consider the angle of repose for the gravel to be 40o and the critical shear stress of the coarse gravel to be 0.456lb/ft2.
Water flows down a rectangular channel that has a width of 2.2 m, a Manning's n of 0.019 and a slope of 1 in 200. Calculate the discharge in the channel when the depth of flow is 0.5 m, 1.0 m, 2.0 m, and 4.0 m. Plot a graph of depth against discharge and comment on its shape, [10 marks] A wide channel has a Manning's number = 0.021, a longitudinal bed slope of 1:250 and conveys 0.XX m3/s/m of...
14.13 (a) only Spreadsheet from HW 3: Manning: 1. Numerically solve for the normal depth using either MS-Excel or Matlab. Hint: your spreadsheet for critical depth in HW3 is a good place to start. 14.13 The channel in Problem 14.7 is excavated in smooth rock to a bed slope of 0.2%. Deter- mine the (a) normal depth of flow, (b) critical slope, and (c) state of flow in the channel. 14.7 A trapezoidal channel has a bed width of 3.5...
summarizr the followung info and write them in your own words and break them into different key points. 6.5 Metering Chamber: 6.5.1 The minimum size of the metering box is governed by the metering area required to obtain a representative test area for the specimen (see 7.2) and for maintenance of reasonable test accuracy. For example, for specimens incorporating air spaces or stud spaces, the metering area shall span an integral number of spaces (see 5.5). The depth of...
summatize the following info and break them into differeng key points. write them in yojr own words apartus 6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...