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Solution
Given
Enthalpy of formation of So3 = -395.7 Kj/mol
Enthalpy of formation of So2 = - 296.8 KJ /mol
Solution
We will use formula for calculating standard heat of reaction
Which is equal to
(Sum of enthalpy of products ) - (sum of enthalpy of reactants)
= (- 2 × 395.7 KJ/mol ) - ( -2 × 296.8 KJ/mol)
= - 197.8 KJ/ mol
But in option( C ) -197.8 KJ is given
So it is already given per mole .
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