Consider the decomposition of sulfur trioxide gas into sulfur dioxide and oxygen 2SO3(g)<- ->2SO2(g) +O2(g) a flask of SO3 is filled to 0.960 M and allowed to decompose. at equilibrium the concentration of SO2 is 0.320 M what is Kc?
Consider the decomposition of sulfur trioxide gas into sulfur dioxide and oxygen 2SO3(g)<- ->2SO2(g) +O2(g) a...
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+O2(g)→2SO3(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur dioxide, oxygen, and sulfur trioxide has the following composition: Calculate the value of the equilibrium constant Kp for this reaction. Round your answer to 2 significant digits. compound pressure at equilibrium SO2 58.3 atm 02 84.7 atm SO3 66.3 atm
Sulfur trioxide is made from the reaction of sulfur dioxide and oxygen. how many grams of SO3 can be made from the reaction of 1.91g SO2 with 1.29g O2? 2 SO2(g) + O2(g)---> 2SO3(g) a) 2.39g b) 3.20g c) 3.23g d) 4.77g e) 6.46g How would i solve this problem?? Im thinking i would use the simplest formula, but im not sure if thats right. And if so, how would i do it??
1. In the gas phase, sulfur dioxide reacts with oxygen to form sulfur trioxide, 2502 + O2 = 2503. An equilibrium mixture at 1000K and 1767 torr had the following mole fractions: x(SO2) = 0.310, x(O2) = 0.250. SO3 was also present. Calculate Koº and AG° at 1000K, assuming all gases behave ideally.
The following thermochemical equation is for the reaction of sulfur dioxide(g) with oxygen(g) to form sulfur trioxide(g). 2SO2(g) + O2(g)2SO3(g) H = -198 kJ How many grams of SO2(g) would have to react to produce 31.9 kJ of energy?
At a given temperature, the equilibrium constant Kc for the reaction 2SO2(g)+O2(g)<==>2SO3(g) is 2.99x10^-3. What is the value of the equilibrium constant for each of the following reactions at that temperature? a. SO2(g)+ 1/2 O2(g)<==> SO3(g) b. 2SO3(g)<==>2SO2(g)+O2(g) c. SO3(g)<==> SO2(g)+ 1/2 O2(g)
Sulfur trioxide is formed from sulfur dioxide and oxygen according to the reaction formula 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g) with the equilibrium constant 2.5 × 1010 at the temperature 5.0 × 102 K. A reaction vessel with a volume of 0.25 L contains from start 0.030 moles of SO2 (g) and 0.050 moles of O2 (g). a) Calculate the partial pressure SO3 (g) after equilibrium is reached at 5.0 × 102 K. b) Will more...
Sulfur dioxide reacts with carbon dioxide to form an equilibrium with sulfur trioxide and carbon monoxide, all gases (see the reaction below). A mixture of 1.81 mole each of sulfur dioxide and carbon dioxide is placed in an 2.1 L container and allowed to reach equilibrium. If the equilibrium constant, Kc, is 1.21 at this temperature, what is the concentration of sulfur trioxide at equilibrium? SO2 (g) + CO2 (g) ⇌ SO3 (2)+ CO (g) Keep extra significant figures during the calculation and...
Sulfur trioxide is made from the oxidation of sulfur dioxide. 2 SO2 + O2 --> 2 SO3. A 16 g sample of SO2, reacted with excess oxygen, gives 18 g SO3. What is the percent yield?
The equilibrium constant for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 7 × 103 at a certain temperature. If at equilibrium, [SO2] = 0.0451 M and [O2] = 0.078 M, what is the equilibrium [SO3]?
Sulfur trioxide is made from the reaction of sulfur dioxide and oxygen. How many grams of SO3 can be made from the reaction of 1.91 g SO2 with 1.29 g O2?