Question

Be sure to answer all parts. During World War II, a portable source of hydrogen gas was needed for weather balloons, and solid metal hydrides were the most convenient form. Many metal hydrides react with water to generate the metal hydroxide and hydrogen. Two candidates were lithium hydride and magnesium hydride. What volume of gas is formed from 1.70 lb of each hydride at 750. torr and 27°C? C H , from Lih LH from MgH2

Answer 1

P= 75otors > T=27C => 27 +273:15 F50 cem 760 T= 300.15 K 7 LiH (Lithium hydride) Wlit = 1.7066 -(1-70 x 453-59)gm 1lb=453.599m While = 771-103 gom MMLiH = 6.95+1 =) 7.95 gmimos nlitt = 771103 mors 7.95 liH + H2O LiOH + H219) V2 7.95 - PH = "H, 2 PN, 1 1 1 193 roko VH = net, 771103/7.95 0:0821 X 300:15 750/760 VH2 = 2422.03 Lit

# Magnessium hydride (MHz) Wrightz = 1.70 lb =) (1.70 x 453.59) gm wag Hz = 771.103 gm MMMgHq = 24-31 + 2(1) => 26-31gmbre? nMyHz = 771.103 mol 26.31 Mg Hz + 2 HOM - Mg(OH)2 + 2H219) ArgHz - 42 MHz = 2x 771 103 m) VH, - S8 8 161 mol 58.6167 X 0.0821 X 300:15 750/760 V = 1463.71 lit dhe