Question

6. O -19.09 points SerCP9 12.P.038. A heat pump has a coefficient of performance of 3.75 and operates with a power consumption of 6.89 x 10 W. (a) How much energy does it deliver into a home during 4 h of continuous operation? (b) How much energy does it extract from the outside air? Need Help? Talk to a Tutor

Answer 1

Solution:

Given:

COP = 3.75

P_i = 6.89 x 10³ W = 6890 W

Part (a) Solution :

Since : for the energy delivered : COP = Q/W

Q = COP x W = COP x P t = (3.75)(6890 W)(4 x 3600 s) = 3.72 x 10⁸ J

Therefore : the heat delivered to the room is 3.72 x 10⁸ J.

Part (b) Solution :

heat extracted from outside = Q - W = (3.72 x 10⁸ J) - (6890 W x 4 x 3600 s) = 2.73 x 10⁸ J

Therefore : heat extracted from outside = 2.73 x 10⁸ J.

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