Part D In a certain hypothetical experiment, the initial concentration of the reactant R is 1.00...
Part D
In a certain hypothetical experiment, the initial concentration of the reactant R is 1.00 mol⋅L−1 , and its rate constant is 0.0150 mol⋅L−1⋅s−1. It follows a zero-order reaction mechanism for the consumption of reactant R.
Plot the graph of concentration versus time. Consider the time intervals as 0, 10, 20, 30, 40, and 50 s.
To sketch the graph first click on 
.
Then select the appropriate graph and plot the appropriate
points.
Homework Answers
The integrated zero order rate law is
[R]t = -kt + [R]0
where [R]t represents the concentration of the R of interest at a particular time, and [R]0 represents the initial concentration.
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Part D
In a certain hypothetical experiment, the initial concentration
of the reactant R is 1.00...
Part A The rate constant for a certain reaction is k = 7.60x10-35-?. If the initial...
Part A The rate constant for a certain reaction is k = 7.60x10-35-?. If the initial reactant concentration was 0.950 mol L-, what will the concentration be after 5.00 minutes? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Part B . If after 65.0 seconds the concentration has dropped to 1.50x10-2 A zero-order reaction has a constant rate of 4.50x10-mol L-8 mol L , what was...
Most of the time, the rate of a reaction depends on the concentration of the reactant....
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
help!!! Problem Statement: How can concentration changes affect a chemical reaction? I, Data Collection: EXPERIMENT #...
help!!!
Problem Statement: How can concentration changes affect a chemical reaction? I, Data Collection: EXPERIMENT # 1 : R BG RG B + + Initial Concentration-I 0.6 0.7 0.8 0.9 - 0.13 Concentration Change-C -0.17 - 0,17 0.17 Ending Concentration-E 0.43 0.53 0.97 1.07 Calculate the change in concentration of each of the substances in the reaction. In the space below, draw a plot of the concentration v. time and label the axes. Identify the chemical substance that corresponds to...
1. The rate constant for a certain reaction is k=3.70x10-3 s-1. If the initial reactant concentration...
1. The rate constant for a certain reaction is k=3.70x10-3 s-1. If the initial reactant concentration was 0.400 M, what will the concentration be after 3.00 minutes? 2. A zero-orderreaction has a constant rate of 3.30x10-4 M/s. If after 80.0 seconds the concentration has dropped to 8.00x20-2 M, what was the initial concentration?
A certain reaction obeys second-order kinetics with respect to its only reactant (call it R) and...
A certain reaction obeys second-order kinetics with respect to its only reactant (call it R) and has a rate constant of 0.0520 L mole-1 s-1. If the initial concentration of reactant R is 0.265 moles/liter, what is the concentration of R after 3.50 minutes? _______________
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows
chemists to predict the reactant concentration after a certain
amount of time, or the time it would take for a certain
concentration to be reached. The integrated rate law for a
first-order reaction is: [A]=[A]0e−kt Now say we are particularly
interested in the time it would take for the concentration to
become one-half of its initial value. Then we could substitute
[A]02 for [A] and rearrange the equation to: t1/2=0.693k This
equation calculates the time...
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a...
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a rate k can be described as follows: In(C) = ln(Co) - kt, where C is the concentration of the reactant at time t, Co is the initial concentration and t is the elapsed time since the reaction started. Consider an initial concentration of Co = 0.3 mol/L. The experiment was repeated n times to give a geometric mean of the concentration at time t...
Part A The rate constant for a certain reaction is k= 6.70x10-35-1 If the initial reactant...
Part A The rate constant for a certain reaction is k= 6.70x10-35-1 If the initial reactant concentration was 0.200 M, what will the concentration be after 20.0 minutes? Express your answer with the appropriate units. ► View Available Hint(s) μΑ ? Value [A] 11 M
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...
The half-life of a reaction, t1/2, is the time it takes for the reactant concentration [A]...
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
Part A The rate constant for a certain reaction is k = 7.60x10-35-?. If the initial reactant concentration was 0.950 mol L-, what will the concentration be after 5.00 minutes? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Part B . If after 65.0 seconds the concentration has dropped to 1.50x10-2 A zero-order reaction has a constant rate of 4.50x10-mol L-8 mol L , what was...
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
help!!!
Problem Statement: How can concentration changes affect a chemical reaction? I, Data Collection: EXPERIMENT # 1 : R BG RG B + + Initial Concentration-I 0.6 0.7 0.8 0.9 - 0.13 Concentration Change-C -0.17 - 0,17 0.17 Ending Concentration-E 0.43 0.53 0.97 1.07 Calculate the change in concentration of each of the substances in the reaction. In the space below, draw a plot of the concentration v. time and label the axes. Identify the chemical substance that corresponds to...
The integrated rate law allows
chemists to predict the reactant concentration after a certain
amount of time, or the time it would take for a certain
concentration to be reached. The integrated rate law for a
first-order reaction is: [A]=[A]0e−kt Now say we are particularly
interested in the time it would take for the concentration to
become one-half of its initial value. Then we could substitute
[A]02 for [A] and rearrange the equation to: t1/2=0.693k This
equation calculates the time...
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a rate k can be described as follows: In(C) = ln(Co) - kt, where C is the concentration of the reactant at time t, Co is the initial concentration and t is the elapsed time since the reaction started. Consider an initial concentration of Co = 0.3 mol/L. The experiment was repeated n times to give a geometric mean of the concentration at time t...
Part A The rate constant for a certain reaction is k= 6.70x10-35-1 If the initial reactant concentration was 0.200 M, what will the concentration be after 20.0 minutes? Express your answer with the appropriate units. ► View Available Hint(s) μΑ ? Value [A] 11 M
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
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