Question

USING PYTHON!

1. a) Programmatically (do not just write a definition!) create a dictionary whose keys are the integers 1 through 10 and whose respective values are the keys cubed (e.g. a key of 5 has a value of 125).

2. b) Write a function that, given a user inputted string, outputs a dictionary where each letter is a key and each value is the letter’s position in the string. Note that you ​must handle cases where a word could contain the same letter more than once​, such as “mongoose” correctly having the letter “o” indexed more than once!

Answer 1

Question 1 :

d = {}
for i in range(1,11):
    d[i]=i*i*i
print(d)

$\color{blue}\underline{Output:}$

{1: 1, 2: 8, 3: 27, 4: 64, 5: 125, 6: 216, 7: 343, 8: 512, 9: 729, 10: 1000}

#############################

Question 2 :

s = input("Enter input: ")
d = {}
for i in range(len(s)):
    x = s[i]
    if not d.get(x):
        d[x] = [i]
    else:
        tmp = d[x]
        tmp.append(i)
        d[x] = tmp
print(d)

$\color{blue}\underline{Output:}$

Enter input: mongoose {'m': [0], 'o': [1, 4, 5], 'n': [2], 'g': [3], 's': [6], 'e': [7]} Process finished with exit code 0

Answer 2

Write a Python program to create a dictionary of student data by taking input from the user,  where each student data contains Rollno (to be considered as key), and marks in 3 subjects (to 

be considered as list of values). e.g. {1 : [45, 40, 35], 2 : [41, 38, 39], 3 : [35, 30, 37]}. Prepare  mark list in the following format:  

Roll No. Mark-1 Mark-2 Mark-3 Total  

 1 45 40 35 120 

stud = {}

mrk = []

print("ENTER ZERO NUMBER FOR EXIT !!!!!!!!!!!!")

print("ENTER STUDENT INFORMATION ------------------------ ")

while True :

    rno = int(input("enter roll no.. :: -- "))

    if rno == 0 :

        break

    else:

         for i in range(3):

             print("enter marks  ",i+1," :: --  ",end = " ")

             n = int(input())

             mrk.append(n)

    stud[rno] = mrk

    mrk = []

print("Records are ------ ",stud)

print("\nRollNo\t Mark1\t Mark2\t Mark3\t Total")

tot = 0

for r in stud:

    print(r,"\t",end=" ")

    for m in stud[r]:

        tot = tot + m

        print(m,"\t",end=" ")

    print(tot)

    tot = 0

Q.6. Write a Python program to take input of a string from the user and then create a dictionary  containing each character of the string along with their frequencies. (e.g. if the string is ‘banana’  then output should be {'b': 1, 'a': 3, 'n': 2}.

 

d = dict()

user = input ("enter a string ::-- ")

lst = list(user)

l = len(lst)

for i in range(l) :

    c = 0

    for j in range(l) :

        if lst[i] == lst[j ]:

            c += 1

    d[lst[i]] = c

print("dictionary is  :: ",d)

Q.7. Write a Python program to create a list of strings by taking input from the user and then create  a dictionary containing each string along with their frequencies. (e.g. if the list is [‘apple’,  ‘banana’, ‘fig’, ‘apple’, ‘fig’, ‘banana’, ‘grapes’, ‘fig’, ‘grapes’, ‘apple’] then output should be  {'apple': 3, 'banana': 2, 'fig': 3, 'grapes': 2}.  

 

lst = []

d = dict()

print("ENTER ZERO NUMBER FOR EXIT !!!!!!!!!!!!")

while True:

    user = input('enter string element :: -- ')

    if user == "0":

        break

    else:

        lst.append(user)

print("LIST ELEMENR ARE :: ",lst)

l = len(lst)

for i in range(l) :

    c = 0

    for j in range(l) :

        if lst[i] == lst[j ]:

            c += 1

    d[lst[i]] = c

print("dictionary is  :: ",d)

Q.8. Write a Python program to input a string that is a list of words separated by commas. Construct  a dictionary that contains all these words as keys and their frequencies as values. Then display  the words with their quantities.  

 

lst = []

d = dict()

user = input ("enter a string ::-- ")

lst = user.split(',')

print("LIST ELEMENR ARE :: ",lst)

l = len(lst)

for i in range(l) :

    c = 0

    for j in range(l) :

        if lst[i] == lst[j ]:

            c += 1

    d[lst[i]] = c

print("dictionary is  :: ",d)