Question

PYTHON 3:

Write a function removeRand() that takes a dictionary d and an integer n as parameters. The function randomly chooses n key-value pairs and removes them from the dictionary d. If n is greater than the number of elements in the dictionary, the function prints a message but does not make any changes to d. If n is equal to the number of elements in d, the function clears the dictionary. Otherwise the function goes through n rounds in which it chooses a random key in the dictionary and removes that key-value pair from the dictionary. The function does not return any values since its purpose is to alter the dictionary. Hint: To select a random key, make a list out of the keys in the dictionary and use methods from the random module to choose one of the list elements. The following shows several example runs of the function. Remember that your runs may differ from what is seen below since the elements eliminated are chosen at random:

Answer 1

import random

def removeRand(d, n):

if n == len(d):

keys = []

for one in d:

keys.append(one)

for i in range(n):

del(d[keys[i]])

print("Yo")

elif n < len(d):

keys = []

for one in d:

keys.append(one)

for i in range(n):

one = random.randint(0, len(keys)-1)

del(d[keys[one]])

d = {1:"hey", 2:"there", 3:"it", 4:"works"}

removeRand(d, 4)

print(d)

# Output: {1: 'hey', 3: 'it'}