Question

Before taking the plunge into videoconferencing, a company ran tests of its current internal computer network. The goal of th
(b) Estimate the least squares linear equation for Transfer Time on File Size. Interpret the fitted intercept and slope. Be s
B. The slope of seconds is the transfer time for a file of size 0 MB OC. The slope of OD. The slope is seconds per megabyte i
OC. The value of means that the average residual is megabytes. The value of s, means that the equation does not describe abou
OD. No, it fits equally well because the value of s, is the same. O E Yes, because the new value of is . (Round to one decima
O A. Yes, because the plot shows a linear pattern. B. No, because the plot shows consistent vertical scatter with no obvious
(Just need help with part F)
File size (MB) File size (MB) Time (sec) 31.1 35.1 35.3 35.7 14.4 28.9 29.6 33.5 21.7 15.3 28.4 11.5 35.7 25.6 36.6 Time (sec
File_size_(MB) Time_(sec)
77 31.1
93 35.1
85 35.3
94 35.7
20 14.4
74 28.9
68 29.6
88 33.5
42 21.7
20 15.3
72 28.4
24 11.5
95 35.7
59 25.6
93 36.6
71 29.1
87 34.3
92 37.2
90 35.6
67 26.8
87 32.6
83 31.2
80 34.1
57 22.8
52 25.4
76 28.9
96 38.7
70 31.8
59 24.2
57 28.1
0 0
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Answer #1

* Please give positive rating- Estimated transtor tinel second) = 7.599 + 0.292 ob (from past 8) (Filesizeme 15 = 7.599 8. 292. Peres se regression fike tile Size (MB) A = 7.599 + 292 Ctime tronsted) - 7.599+ 292x15 - 11.980 inter Changed the deperde

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Answer #2

Solution part F:

Perform regression in excel

File Home Insert Page Layout Formulas Data Colectica Review View Help Tell me what you want to do Clear Reapply Advanced Exte

we get

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.97208
R Square 0.94494
Adjusted R Square 0.942973
Standard Error 5.267833
Observations 30
ANOVA
df SS MS F Significance F
Regression 1 13334.86 13334.86 480.5346 3.61E-19
Residual 28 777.0018 27.75006
Total 29 14111.87
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept -20.0454 4.260264 -4.70521 6.21E-05 -28.7722 -11.3187
Time_(sec)-(x) 3.104371 0.141616 21.9211 3.61E-19 2.814284 3.394457

ANSWER:

regression eq i

y=-20.0454+3.104371*x

Filesize=-20.0454+3.104371*time

For x=15 we need to predict y

we get

Filesize=-20.0454+3.104371*time

=-20.0454+3.104371*15

= 26.52016

ANSWER:

(B)

Do the regression in reverse and use the new fitted line.The estimated file size is 26.52 Mb

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