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A 50.0-kg block is being pushed up a 12.0° slope by a force of 300 N...

A 50.0-kg block is being pushed up a 12.0° slope by a force of 300 N which is directed 30.0° below the slope. The coefficient of kinetic friction between the block and the slope is 0.200. What is the acceleration of the block?

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Answer #1

a = (300*cos(30 degrees) - 50*9.8*sin(15 degrees)-0.2*(50*9.8*cos(15 degrees)+300*sin(30 degrees)))/50 = 0.167 m/s2

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