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A 65.0 kg block is being pushed up a 11.0° slope by a force of 270.0...

A 65.0 kg block is being pushed up a 11.0° slope by a force of 270.0 N which is parallel to the slope. What is the coefficient of kinetic friction between the block and the slope, if the block is moving up the slope at a constant velocity?

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Answer #1

From Newton's second law

Since object is moving with constant velocity =>ax=0

F-Ff-mgsin11=0

F-ukmgCos11-mgsin11=0

270-uk*65*9.8*Cos11-65*9.8*Sin11=0

uk=0.2374

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