3) A box of 25 kg is pushed horizontally, with a force of 200 N, up...
3) A box of 25 kg is pushed horizontally, with a force of 200 N,
up a 37degrees
(with respect to the horizontal) frictionless incline.
a) Find the Normal force
What is the acceleration of the box?
b) Now if friction is present. What value of the coefficient of
kinetic
friction is necessary such that the box is pushed with constant
velocity.
Homework Answers
a) N + 200sin37 = 25g
N = 25 x 9.81 - 200sin37 =124.89 N
Fcos37 = ma
a = 200cos37 / 25 =6.34 m/s2
b) constant velocity means zero acc.
so friction = Fcos37
u .124.89 = 200cos37
u =1.28
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