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A box of mass 50.95 kg is pushed up the slope .  If the coefficient of static...

A box of mass 50.95 kg is pushed up the slope .  If the coefficient of static friction is 0.12 and the coefficient of kinetic friction is 0.02, find the force required to start pushing the box.

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Answer #1

Answer :

the minimum force required to start pushing the box

F = mg sin +f

where f = friction force = N = mgcos

F = mg sin + mgcos

F = mg (sin + cos)

F = 50.95 x 9.8 ((sin + 0.12 cos)

F = 499.31 (sin + 0.12cos)

put the value of angle from slope and get the Force required to start pushing the box.

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