Question

QUESTION 25 What is the oxidation number for the chromium atom in the following molecules? K2Cr204: Cro32

Answer 1

K2Cr2O4 oxidation state of Chromium is +3.

CrO3 2- oxidation state of Chromium is +4.

For K2Cr2O4 since whole molecule oxidation state sum is 0, and o considered state of oxygen is -2 and potassium is +1 then calculated oxidation state of Chromium is +3

For CrO3 2- since it's a ion so whole molecule oxidation state sum is equal to the charge of ion so -2 and considered oxidation state of oxygen is -2 so calculated oxidation state of Chromium is +4

K₂C%204 И. Lets oxidation number of choomium = n 2(+)+2x+4(-2)=0 2 + 2n - 8 = 0 22= 6 n = +3 Oxidation number of chromium in K₂ Coz Oq is +3. Co O2- Lets oxidation number of chromium = n 4+3(-2)=-2 n-6 = -2 n = + 4 oxidation number of chromium in CO is +4.