In drug discovery, the value “log P” (the log of the octanol-water partition coefficient) is often...
In drug discovery, the value “log P” (the log of the octanol-water partition coefficient) is often used as an estimate of the lipophilicity of a potential new drug.
log P = log([solute]octanol/[solute]water)
The log P value for nicotine is 1.09. If 20 mL of 0.10 g/mL nicotine solution in water is extracted with 20 mL of octanol, how much nicotine is removed from the water layer into the octanol layer? If the same water solution is extracted with (2 x 10 mL) of octanol, how much nicotine is removed from the water layer? Both methods employ a total of 20 mL octanol for the extraction, but are they equally effective for removing nicotine from a water solution? Which method is more effective?
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In drug discovery, the value “log P” (the log of the
octanol-water partition coefficient) is often...
An important parameter is called the octanol-water partition coefficient, Kow, which is related to the tendency...
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A monoprotic acid (Ka = 4.31 x 10) has a partition coefficient of 4.4 (in favor of octanol) when distributed between wa...
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A monoprotic acid (Ka = 4.31 x 10-5) has a partition coefficient of 4.4 in favor of octanol) when distributed between w...
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Question / Not yet answered Marked out of The partition coefficient Pag question Select one: a....
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question 9! parts a and b!
table shows data after 3 extractions!!!
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A monoprotic acid (Ka = 4.31 x 10-5) has a partition coefficient of 4.4 in favor of octanol) when distributed between water and octanol. Find the concentration of the acid remaining in the aqueous phase when when 100 mL of 0.10 M aqueous solution of the acid is extracted with 27 mL of octanol at pH 4.00. a. 0.17 M b.0.546 M OC. 0.01 M o d. 0.0546 M
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steps/procedures includes for reference)
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