Solution:
Given in the question
Mean = 100
Standard Deviation = 15
We need to find
P(106<=Xbar<=132) = P(Xbar<132) - P(Xbar<106)
Z = (132-100)/15 = 2.13
Z = (106-100)/15 = 0.4
P(106<=Xbar<=132) = P(Xbar<132) - P(Xbar<106) = 0.9834
- 0.6554 = 0.328
So 32.8% area covered in the shaded region.
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